3.1994 \(\int (a+b x) (d+e x)^3 (a^2+2 a b x+b^2 x^2)^{5/2} \, dx\)

Optimal. Leaf size=172 \[ \frac {e^2 \sqrt {a^2+2 a b x+b^2 x^2} (a+b x)^8 (b d-a e)}{3 b^4}+\frac {3 e \sqrt {a^2+2 a b x+b^2 x^2} (a+b x)^7 (b d-a e)^2}{8 b^4}+\frac {\sqrt {a^2+2 a b x+b^2 x^2} (a+b x)^6 (b d-a e)^3}{7 b^4}+\frac {e^3 \sqrt {a^2+2 a b x+b^2 x^2} (a+b x)^9}{10 b^4} \]

[Out]

1/7*(-a*e+b*d)^3*(b*x+a)^6*((b*x+a)^2)^(1/2)/b^4+3/8*e*(-a*e+b*d)^2*(b*x+a)^7*((b*x+a)^2)^(1/2)/b^4+1/3*e^2*(-
a*e+b*d)*(b*x+a)^8*((b*x+a)^2)^(1/2)/b^4+1/10*e^3*(b*x+a)^9*((b*x+a)^2)^(1/2)/b^4

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Rubi [A]  time = 0.24, antiderivative size = 172, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 33, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {770, 21, 43} \[ \frac {e^2 \sqrt {a^2+2 a b x+b^2 x^2} (a+b x)^8 (b d-a e)}{3 b^4}+\frac {3 e \sqrt {a^2+2 a b x+b^2 x^2} (a+b x)^7 (b d-a e)^2}{8 b^4}+\frac {\sqrt {a^2+2 a b x+b^2 x^2} (a+b x)^6 (b d-a e)^3}{7 b^4}+\frac {e^3 \sqrt {a^2+2 a b x+b^2 x^2} (a+b x)^9}{10 b^4} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x)*(d + e*x)^3*(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]

[Out]

((b*d - a*e)^3*(a + b*x)^6*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(7*b^4) + (3*e*(b*d - a*e)^2*(a + b*x)^7*Sqrt[a^2 +
2*a*b*x + b^2*x^2])/(8*b^4) + (e^2*(b*d - a*e)*(a + b*x)^8*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(3*b^4) + (e^3*(a +
b*x)^9*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(10*b^4)

Rule 21

Int[(u_.)*((a_) + (b_.)*(v_))^(m_.)*((c_) + (d_.)*(v_))^(n_.), x_Symbol] :> Dist[(b/d)^m, Int[u*(c + d*v)^(m +
n), x], x] /; FreeQ[{a, b, c, d, n}, x] && EqQ[b*c - a*d, 0] && IntegerQ[m] && ( !IntegerQ[n] || SimplerQ[c +
d*x, a + b*x])

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 770

Int[((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Dis
t[(a + b*x + c*x^2)^FracPart[p]/(c^IntPart[p]*(b/2 + c*x)^(2*FracPart[p])), Int[(d + e*x)^m*(f + g*x)*(b/2 + c
*x)^(2*p), x], x] /; FreeQ[{a, b, c, d, e, f, g, m}, x] && EqQ[b^2 - 4*a*c, 0]

Rubi steps

\begin {align*} \int (a+b x) (d+e x)^3 \left (a^2+2 a b x+b^2 x^2\right )^{5/2} \, dx &=\frac {\sqrt {a^2+2 a b x+b^2 x^2} \int (a+b x) \left (a b+b^2 x\right )^5 (d+e x)^3 \, dx}{b^4 \left (a b+b^2 x\right )}\\ &=\frac {\left (b \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int (a+b x)^6 (d+e x)^3 \, dx}{a b+b^2 x}\\ &=\frac {\left (b \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int \left (\frac {(b d-a e)^3 (a+b x)^6}{b^3}+\frac {3 e (b d-a e)^2 (a+b x)^7}{b^3}+\frac {3 e^2 (b d-a e) (a+b x)^8}{b^3}+\frac {e^3 (a+b x)^9}{b^3}\right ) \, dx}{a b+b^2 x}\\ &=\frac {(b d-a e)^3 (a+b x)^6 \sqrt {a^2+2 a b x+b^2 x^2}}{7 b^4}+\frac {3 e (b d-a e)^2 (a+b x)^7 \sqrt {a^2+2 a b x+b^2 x^2}}{8 b^4}+\frac {e^2 (b d-a e) (a+b x)^8 \sqrt {a^2+2 a b x+b^2 x^2}}{3 b^4}+\frac {e^3 (a+b x)^9 \sqrt {a^2+2 a b x+b^2 x^2}}{10 b^4}\\ \end {align*}

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Mathematica [A]  time = 0.10, size = 294, normalized size = 1.71 \[ \frac {x \sqrt {(a+b x)^2} \left (210 a^6 \left (4 d^3+6 d^2 e x+4 d e^2 x^2+e^3 x^3\right )+252 a^5 b x \left (10 d^3+20 d^2 e x+15 d e^2 x^2+4 e^3 x^3\right )+210 a^4 b^2 x^2 \left (20 d^3+45 d^2 e x+36 d e^2 x^2+10 e^3 x^3\right )+120 a^3 b^3 x^3 \left (35 d^3+84 d^2 e x+70 d e^2 x^2+20 e^3 x^3\right )+45 a^2 b^4 x^4 \left (56 d^3+140 d^2 e x+120 d e^2 x^2+35 e^3 x^3\right )+10 a b^5 x^5 \left (84 d^3+216 d^2 e x+189 d e^2 x^2+56 e^3 x^3\right )+b^6 x^6 \left (120 d^3+315 d^2 e x+280 d e^2 x^2+84 e^3 x^3\right )\right )}{840 (a+b x)} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)*(d + e*x)^3*(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]

[Out]

(x*Sqrt[(a + b*x)^2]*(210*a^6*(4*d^3 + 6*d^2*e*x + 4*d*e^2*x^2 + e^3*x^3) + 252*a^5*b*x*(10*d^3 + 20*d^2*e*x +
15*d*e^2*x^2 + 4*e^3*x^3) + 210*a^4*b^2*x^2*(20*d^3 + 45*d^2*e*x + 36*d*e^2*x^2 + 10*e^3*x^3) + 120*a^3*b^3*x
^3*(35*d^3 + 84*d^2*e*x + 70*d*e^2*x^2 + 20*e^3*x^3) + 45*a^2*b^4*x^4*(56*d^3 + 140*d^2*e*x + 120*d*e^2*x^2 +
35*e^3*x^3) + 10*a*b^5*x^5*(84*d^3 + 216*d^2*e*x + 189*d*e^2*x^2 + 56*e^3*x^3) + b^6*x^6*(120*d^3 + 315*d^2*e*
x + 280*d*e^2*x^2 + 84*e^3*x^3)))/(840*(a + b*x))

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fricas [B]  time = 1.00, size = 327, normalized size = 1.90 \[ \frac {1}{10} \, b^{6} e^{3} x^{10} + a^{6} d^{3} x + \frac {1}{3} \, {\left (b^{6} d e^{2} + 2 \, a b^{5} e^{3}\right )} x^{9} + \frac {3}{8} \, {\left (b^{6} d^{2} e + 6 \, a b^{5} d e^{2} + 5 \, a^{2} b^{4} e^{3}\right )} x^{8} + \frac {1}{7} \, {\left (b^{6} d^{3} + 18 \, a b^{5} d^{2} e + 45 \, a^{2} b^{4} d e^{2} + 20 \, a^{3} b^{3} e^{3}\right )} x^{7} + \frac {1}{2} \, {\left (2 \, a b^{5} d^{3} + 15 \, a^{2} b^{4} d^{2} e + 20 \, a^{3} b^{3} d e^{2} + 5 \, a^{4} b^{2} e^{3}\right )} x^{6} + \frac {3}{5} \, {\left (5 \, a^{2} b^{4} d^{3} + 20 \, a^{3} b^{3} d^{2} e + 15 \, a^{4} b^{2} d e^{2} + 2 \, a^{5} b e^{3}\right )} x^{5} + \frac {1}{4} \, {\left (20 \, a^{3} b^{3} d^{3} + 45 \, a^{4} b^{2} d^{2} e + 18 \, a^{5} b d e^{2} + a^{6} e^{3}\right )} x^{4} + {\left (5 \, a^{4} b^{2} d^{3} + 6 \, a^{5} b d^{2} e + a^{6} d e^{2}\right )} x^{3} + \frac {3}{2} \, {\left (2 \, a^{5} b d^{3} + a^{6} d^{2} e\right )} x^{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(e*x+d)^3*(b^2*x^2+2*a*b*x+a^2)^(5/2),x, algorithm="fricas")

[Out]

1/10*b^6*e^3*x^10 + a^6*d^3*x + 1/3*(b^6*d*e^2 + 2*a*b^5*e^3)*x^9 + 3/8*(b^6*d^2*e + 6*a*b^5*d*e^2 + 5*a^2*b^4
*e^3)*x^8 + 1/7*(b^6*d^3 + 18*a*b^5*d^2*e + 45*a^2*b^4*d*e^2 + 20*a^3*b^3*e^3)*x^7 + 1/2*(2*a*b^5*d^3 + 15*a^2
*b^4*d^2*e + 20*a^3*b^3*d*e^2 + 5*a^4*b^2*e^3)*x^6 + 3/5*(5*a^2*b^4*d^3 + 20*a^3*b^3*d^2*e + 15*a^4*b^2*d*e^2
+ 2*a^5*b*e^3)*x^5 + 1/4*(20*a^3*b^3*d^3 + 45*a^4*b^2*d^2*e + 18*a^5*b*d*e^2 + a^6*e^3)*x^4 + (5*a^4*b^2*d^3 +
6*a^5*b*d^2*e + a^6*d*e^2)*x^3 + 3/2*(2*a^5*b*d^3 + a^6*d^2*e)*x^2

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giac [B]  time = 0.22, size = 523, normalized size = 3.04 \[ \frac {1}{10} \, b^{6} x^{10} e^{3} \mathrm {sgn}\left (b x + a\right ) + \frac {1}{3} \, b^{6} d x^{9} e^{2} \mathrm {sgn}\left (b x + a\right ) + \frac {3}{8} \, b^{6} d^{2} x^{8} e \mathrm {sgn}\left (b x + a\right ) + \frac {1}{7} \, b^{6} d^{3} x^{7} \mathrm {sgn}\left (b x + a\right ) + \frac {2}{3} \, a b^{5} x^{9} e^{3} \mathrm {sgn}\left (b x + a\right ) + \frac {9}{4} \, a b^{5} d x^{8} e^{2} \mathrm {sgn}\left (b x + a\right ) + \frac {18}{7} \, a b^{5} d^{2} x^{7} e \mathrm {sgn}\left (b x + a\right ) + a b^{5} d^{3} x^{6} \mathrm {sgn}\left (b x + a\right ) + \frac {15}{8} \, a^{2} b^{4} x^{8} e^{3} \mathrm {sgn}\left (b x + a\right ) + \frac {45}{7} \, a^{2} b^{4} d x^{7} e^{2} \mathrm {sgn}\left (b x + a\right ) + \frac {15}{2} \, a^{2} b^{4} d^{2} x^{6} e \mathrm {sgn}\left (b x + a\right ) + 3 \, a^{2} b^{4} d^{3} x^{5} \mathrm {sgn}\left (b x + a\right ) + \frac {20}{7} \, a^{3} b^{3} x^{7} e^{3} \mathrm {sgn}\left (b x + a\right ) + 10 \, a^{3} b^{3} d x^{6} e^{2} \mathrm {sgn}\left (b x + a\right ) + 12 \, a^{3} b^{3} d^{2} x^{5} e \mathrm {sgn}\left (b x + a\right ) + 5 \, a^{3} b^{3} d^{3} x^{4} \mathrm {sgn}\left (b x + a\right ) + \frac {5}{2} \, a^{4} b^{2} x^{6} e^{3} \mathrm {sgn}\left (b x + a\right ) + 9 \, a^{4} b^{2} d x^{5} e^{2} \mathrm {sgn}\left (b x + a\right ) + \frac {45}{4} \, a^{4} b^{2} d^{2} x^{4} e \mathrm {sgn}\left (b x + a\right ) + 5 \, a^{4} b^{2} d^{3} x^{3} \mathrm {sgn}\left (b x + a\right ) + \frac {6}{5} \, a^{5} b x^{5} e^{3} \mathrm {sgn}\left (b x + a\right ) + \frac {9}{2} \, a^{5} b d x^{4} e^{2} \mathrm {sgn}\left (b x + a\right ) + 6 \, a^{5} b d^{2} x^{3} e \mathrm {sgn}\left (b x + a\right ) + 3 \, a^{5} b d^{3} x^{2} \mathrm {sgn}\left (b x + a\right ) + \frac {1}{4} \, a^{6} x^{4} e^{3} \mathrm {sgn}\left (b x + a\right ) + a^{6} d x^{3} e^{2} \mathrm {sgn}\left (b x + a\right ) + \frac {3}{2} \, a^{6} d^{2} x^{2} e \mathrm {sgn}\left (b x + a\right ) + a^{6} d^{3} x \mathrm {sgn}\left (b x + a\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(e*x+d)^3*(b^2*x^2+2*a*b*x+a^2)^(5/2),x, algorithm="giac")

[Out]

1/10*b^6*x^10*e^3*sgn(b*x + a) + 1/3*b^6*d*x^9*e^2*sgn(b*x + a) + 3/8*b^6*d^2*x^8*e*sgn(b*x + a) + 1/7*b^6*d^3
*x^7*sgn(b*x + a) + 2/3*a*b^5*x^9*e^3*sgn(b*x + a) + 9/4*a*b^5*d*x^8*e^2*sgn(b*x + a) + 18/7*a*b^5*d^2*x^7*e*s
gn(b*x + a) + a*b^5*d^3*x^6*sgn(b*x + a) + 15/8*a^2*b^4*x^8*e^3*sgn(b*x + a) + 45/7*a^2*b^4*d*x^7*e^2*sgn(b*x
+ a) + 15/2*a^2*b^4*d^2*x^6*e*sgn(b*x + a) + 3*a^2*b^4*d^3*x^5*sgn(b*x + a) + 20/7*a^3*b^3*x^7*e^3*sgn(b*x + a
) + 10*a^3*b^3*d*x^6*e^2*sgn(b*x + a) + 12*a^3*b^3*d^2*x^5*e*sgn(b*x + a) + 5*a^3*b^3*d^3*x^4*sgn(b*x + a) + 5
/2*a^4*b^2*x^6*e^3*sgn(b*x + a) + 9*a^4*b^2*d*x^5*e^2*sgn(b*x + a) + 45/4*a^4*b^2*d^2*x^4*e*sgn(b*x + a) + 5*a
^4*b^2*d^3*x^3*sgn(b*x + a) + 6/5*a^5*b*x^5*e^3*sgn(b*x + a) + 9/2*a^5*b*d*x^4*e^2*sgn(b*x + a) + 6*a^5*b*d^2*
x^3*e*sgn(b*x + a) + 3*a^5*b*d^3*x^2*sgn(b*x + a) + 1/4*a^6*x^4*e^3*sgn(b*x + a) + a^6*d*x^3*e^2*sgn(b*x + a)
+ 3/2*a^6*d^2*x^2*e*sgn(b*x + a) + a^6*d^3*x*sgn(b*x + a)

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maple [B]  time = 0.05, size = 380, normalized size = 2.21 \[ \frac {\left (84 e^{3} b^{6} x^{9}+560 x^{8} e^{3} a \,b^{5}+280 x^{8} d \,e^{2} b^{6}+1575 x^{7} e^{3} a^{2} b^{4}+1890 x^{7} d \,e^{2} a \,b^{5}+315 x^{7} d^{2} e \,b^{6}+2400 x^{6} e^{3} a^{3} b^{3}+5400 x^{6} d \,e^{2} a^{2} b^{4}+2160 x^{6} d^{2} e a \,b^{5}+120 x^{6} d^{3} b^{6}+2100 x^{5} e^{3} a^{4} b^{2}+8400 x^{5} d \,e^{2} a^{3} b^{3}+6300 x^{5} d^{2} e \,a^{2} b^{4}+840 x^{5} d^{3} a \,b^{5}+1008 x^{4} e^{3} a^{5} b +7560 x^{4} d \,e^{2} a^{4} b^{2}+10080 x^{4} d^{2} e \,a^{3} b^{3}+2520 x^{4} d^{3} a^{2} b^{4}+210 x^{3} e^{3} a^{6}+3780 x^{3} d \,e^{2} a^{5} b +9450 x^{3} d^{2} e \,a^{4} b^{2}+4200 x^{3} d^{3} a^{3} b^{3}+840 a^{6} d \,e^{2} x^{2}+5040 a^{5} b \,d^{2} e \,x^{2}+4200 a^{4} b^{2} d^{3} x^{2}+1260 x \,d^{2} e \,a^{6}+2520 x \,d^{3} a^{5} b +840 d^{3} a^{6}\right ) \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}} x}{840 \left (b x +a \right )^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)*(e*x+d)^3*(b^2*x^2+2*a*b*x+a^2)^(5/2),x)

[Out]

1/840*x*(84*b^6*e^3*x^9+560*a*b^5*e^3*x^8+280*b^6*d*e^2*x^8+1575*a^2*b^4*e^3*x^7+1890*a*b^5*d*e^2*x^7+315*b^6*
d^2*e*x^7+2400*a^3*b^3*e^3*x^6+5400*a^2*b^4*d*e^2*x^6+2160*a*b^5*d^2*e*x^6+120*b^6*d^3*x^6+2100*a^4*b^2*e^3*x^
5+8400*a^3*b^3*d*e^2*x^5+6300*a^2*b^4*d^2*e*x^5+840*a*b^5*d^3*x^5+1008*a^5*b*e^3*x^4+7560*a^4*b^2*d*e^2*x^4+10
080*a^3*b^3*d^2*e*x^4+2520*a^2*b^4*d^3*x^4+210*a^6*e^3*x^3+3780*a^5*b*d*e^2*x^3+9450*a^4*b^2*d^2*e*x^3+4200*a^
3*b^3*d^3*x^3+840*a^6*d*e^2*x^2+5040*a^5*b*d^2*e*x^2+4200*a^4*b^2*d^3*x^2+1260*a^6*d^2*e*x+2520*a^5*b*d^3*x+84
0*a^6*d^3)*((b*x+a)^2)^(5/2)/(b*x+a)^5

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maxima [B]  time = 0.60, size = 693, normalized size = 4.03 \[ \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}} e^{3} x^{3}}{10 \, b} + \frac {1}{6} \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a d^{3} x + \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a^{4} e^{3} x}{6 \, b^{3}} - \frac {13 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}} a e^{3} x^{2}}{90 \, b^{2}} + \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a^{2} d^{3}}{6 \, b} + \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a^{5} e^{3}}{6 \, b^{4}} + \frac {29 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}} a^{2} e^{3} x}{180 \, b^{3}} - \frac {209 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}} a^{3} e^{3}}{1260 \, b^{4}} - \frac {{\left (3 \, b d e^{2} + a e^{3}\right )} {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a^{3} x}{6 \, b^{3}} + \frac {{\left (b d^{2} e + a d e^{2}\right )} {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a^{2} x}{2 \, b^{2}} - \frac {{\left (b d^{3} + 3 \, a d^{2} e\right )} {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a x}{6 \, b} + \frac {{\left (3 \, b d e^{2} + a e^{3}\right )} {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}} x^{2}}{9 \, b^{2}} - \frac {{\left (3 \, b d e^{2} + a e^{3}\right )} {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a^{4}}{6 \, b^{4}} + \frac {{\left (b d^{2} e + a d e^{2}\right )} {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a^{3}}{2 \, b^{3}} - \frac {{\left (b d^{3} + 3 \, a d^{2} e\right )} {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} a^{2}}{6 \, b^{2}} - \frac {11 \, {\left (3 \, b d e^{2} + a e^{3}\right )} {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}} a x}{72 \, b^{3}} + \frac {3 \, {\left (b d^{2} e + a d e^{2}\right )} {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}} x}{8 \, b^{2}} + \frac {83 \, {\left (3 \, b d e^{2} + a e^{3}\right )} {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}} a^{2}}{504 \, b^{4}} - \frac {27 \, {\left (b d^{2} e + a d e^{2}\right )} {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}} a}{56 \, b^{3}} + \frac {{\left (b d^{3} + 3 \, a d^{2} e\right )} {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}}}{7 \, b^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(e*x+d)^3*(b^2*x^2+2*a*b*x+a^2)^(5/2),x, algorithm="maxima")

[Out]

1/10*(b^2*x^2 + 2*a*b*x + a^2)^(7/2)*e^3*x^3/b + 1/6*(b^2*x^2 + 2*a*b*x + a^2)^(5/2)*a*d^3*x + 1/6*(b^2*x^2 +
2*a*b*x + a^2)^(5/2)*a^4*e^3*x/b^3 - 13/90*(b^2*x^2 + 2*a*b*x + a^2)^(7/2)*a*e^3*x^2/b^2 + 1/6*(b^2*x^2 + 2*a*
b*x + a^2)^(5/2)*a^2*d^3/b + 1/6*(b^2*x^2 + 2*a*b*x + a^2)^(5/2)*a^5*e^3/b^4 + 29/180*(b^2*x^2 + 2*a*b*x + a^2
)^(7/2)*a^2*e^3*x/b^3 - 209/1260*(b^2*x^2 + 2*a*b*x + a^2)^(7/2)*a^3*e^3/b^4 - 1/6*(3*b*d*e^2 + a*e^3)*(b^2*x^
2 + 2*a*b*x + a^2)^(5/2)*a^3*x/b^3 + 1/2*(b*d^2*e + a*d*e^2)*(b^2*x^2 + 2*a*b*x + a^2)^(5/2)*a^2*x/b^2 - 1/6*(
b*d^3 + 3*a*d^2*e)*(b^2*x^2 + 2*a*b*x + a^2)^(5/2)*a*x/b + 1/9*(3*b*d*e^2 + a*e^3)*(b^2*x^2 + 2*a*b*x + a^2)^(
7/2)*x^2/b^2 - 1/6*(3*b*d*e^2 + a*e^3)*(b^2*x^2 + 2*a*b*x + a^2)^(5/2)*a^4/b^4 + 1/2*(b*d^2*e + a*d*e^2)*(b^2*
x^2 + 2*a*b*x + a^2)^(5/2)*a^3/b^3 - 1/6*(b*d^3 + 3*a*d^2*e)*(b^2*x^2 + 2*a*b*x + a^2)^(5/2)*a^2/b^2 - 11/72*(
3*b*d*e^2 + a*e^3)*(b^2*x^2 + 2*a*b*x + a^2)^(7/2)*a*x/b^3 + 3/8*(b*d^2*e + a*d*e^2)*(b^2*x^2 + 2*a*b*x + a^2)
^(7/2)*x/b^2 + 83/504*(3*b*d*e^2 + a*e^3)*(b^2*x^2 + 2*a*b*x + a^2)^(7/2)*a^2/b^4 - 27/56*(b*d^2*e + a*d*e^2)*
(b^2*x^2 + 2*a*b*x + a^2)^(7/2)*a/b^3 + 1/7*(b*d^3 + 3*a*d^2*e)*(b^2*x^2 + 2*a*b*x + a^2)^(7/2)/b^2

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \left (a+b\,x\right )\,{\left (d+e\,x\right )}^3\,{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{5/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x)*(d + e*x)^3*(a^2 + b^2*x^2 + 2*a*b*x)^(5/2),x)

[Out]

int((a + b*x)*(d + e*x)^3*(a^2 + b^2*x^2 + 2*a*b*x)^(5/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a + b x\right ) \left (d + e x\right )^{3} \left (\left (a + b x\right )^{2}\right )^{\frac {5}{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)*(e*x+d)**3*(b**2*x**2+2*a*b*x+a**2)**(5/2),x)

[Out]

Integral((a + b*x)*(d + e*x)**3*((a + b*x)**2)**(5/2), x)

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